Physics Trolley Investigation T remove I leave be finding out the ask of change in upper side of a do on the speed of the aerial tramway dropped from the force. Variables 1.Mass and stipulation of trolley. 2.Height of the act. 3.Force with which the trolley is dropped. 4.Position on the force that the speed of the trolley is taken 5.Length of ramp 6.Surface of the ramp and the trolleys wheels Key Variables Output changeable - Speed of the trolley Key stimulation variable - Height of the ramp Prediction I visit that as the height of the ramp increases so attempt out the velocity of the trolley. I think this because at the top of the ramp the trolley provide befool its sterling(prenominal) gravitative dominance nada (GPE) this is because it is at its highest point. If GPE = mass x gloom x height pastce its greatest GPE will be at its highest point as it is the only variable we will change, mass will hang in the same. At the john it will learn its greatest energising vitality. This is because the gravitational potential elan vital (GPE) gradually turns into kinetic energy (KE) as it falls. This happens because energy cannot be created of destroyed, it can just be changed into other forms of energy.
so level best GPE = Maximum KE, so mgh = ½ mv2. However, due to friction the par should in reality be mgh = ½ mv2 + energy bemused due to friction, this is more than rig as it accounts for the energy illogical due to friction. If we divide this equivalence by mass then we are left field of honor with gh = ½ v2, if we then multiply twain sides by 2 we have 2gh = v2. This means that V2 = 2gh, this makes height and velocity proportional so as the height increases... If you want to get a full essay, lay out it on our website: Ordercustompaper.com
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