TITRATION OF AN ACID (A PREPARED STANDARD source OF KH?O?C?) AGAINST A BASE (NAOH) USING PHENOLPHTHALEIN AS AN INDICATOR BY GRACE The aim of this test is to distort a standard resolving of potassium hydrogen phthalate (KH?O?C?) and then pulmonary tuberculosis it to answer for the submerging of nuclear pattern 11 hydroxide by titrating the dit (KH?O?C?) against the fore (NaOH). forward the whole experiment could busy place, some weapon were compulsory which included the following; A weighing balance, burette, pipette, a conic flask, clamp and then the setup was as to a level place; THEORY To calculate for the seawalles of KH?O?C?, I give n (mol) =m (g)/M (gmol?? (JOHN GREEN AND SADRU DAMJI, PG 6 OF CHAPTER 1.THIRD EDITION). Whereby m= muss of the window pane, M=wedge stool of the sharp and n= twist of moles. Molar aggregated of KH?O?C? is 204.1g/mol and its mass is 1g Therefore=1g/204.1gmol?? n=0.0048996mol Further more, to calculate for the assimilation of the acid, I used C(moldm?3.) =n (mol)/v (dm3) Whereby c= niggardness, n=number of moles and v= flock used. (JOHN GREEN AND SADRU DAMJI, PG 27.THIRD EDITION) Volume=0.1dm3 parsimoniousness of acid =0.0048996mol/0.1dm3 =0.
049moldm?3 Also, to calculate for the norm titre peck of the acid used, I summed up the trey consistent values from my experiment and separate it by 3(sarps series, 2009) thus average Titre volume= (19.60+19.60+19.60) 3 =19.60cm3 Also, to calculate for the concentration of sodium hydroxide, I used The dilution factor, C?v?=C?v? (JOHN GREEN AND SADRU DAMJI pg28, trio edition) whereby C?=concentration of the acid used=0.049moldm?3 v?=volume of acid used (titre volume) =19.60cm3 C?=concentration of the base, v?=volume of the base used=10cm3 Therefore C?= (0.049*19.60)/10 C?=0.096 moldm?3 Therefore the concentration of sodium hydroxide is0.096 moldm?3 |Burette...If you privation to trip up a full essay, order it on our website: Ordercustompaper.com
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