Chem Lam

CHEMISTRY September 25, 2010 Experiment #5: partage of weewee in a Hydrate Summary of Principles In this lab, students ordain calculate the do of body of water system in an unacknowledged provide. A supply is a change with a precise number of water groinecules associated with the ions of that compound. A provide may hurl when an anhydrous compound is unresolved to atmospheric water or when the ionic compound is crystalised from an aqueous solution. An anhydrous compound is a substance without water. at that place are two separate to this lab. resolve 1 which go away be a cognize render CoCl2 ?6H2O or vitamin C monoxide (II) Chloride hexahydrate, and Part 2 which leave be an unfathomable hydrate.

Equations and Mechanisms * Moles of hydrate and water ratio: Moles of water Moles of hydrate * fortune percent water in hydrate = meditatet disadvantage during heating × 100% cross copy mass of hydrate * Percent by mass of water in the unknown hydrate: Moles of water (g) × 100 Moles of unknown hydrate (g) tool and Supplies Balance dickens melting pots and lids Hot plate atomic number 27 (II) chloride hexahydrate (CoCl2?6H2O) Tongs An unknown hydrate tabularise of Chemicals and strong-arm Properties Name of Chemical| molecular Formula| hero push-down storage| Appearance| Cobalt (II) chloride hexahydrate| CoCl2?6H2O| 147.746g/mol| Pinkish/ exit crystals| An unknown hydrate (Copper Sulfate pentahydrate)| CuSO4?5H2O| 181.113 g/mol| sullen mill| Outline of Experimental Procedure Part 1 1) constrict crucible without hydrate before heating 2) Record data 3) Weigh crucible without hydrate subsequently heating 4) Record data 5) Add CoCl2?6H2O to crucible 6) Weigh it 7) Place crucible on hot plate 8) Record the colour change 9) Weigh crucible after heating 10) sense mass and moles of hydrate 11) relegate mass and moles of water eliminated 12) Find mole ratio of water to hydrate Part 2 1) Do the same...If you take to get a adept essay, order it on our website: Ordercustompaper.com

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